Year 5 Maths · Measurement & Space

Designing Dinosaur Enclosures: Perimeter and Area

You are the park designer at Cretaceous Cove. Work out how much fencing each enclosure needs and how much ground space each dinosaur gets — using perimeter and area of rectangles.

Section 1 · Perimeter

Fencing the Enclosure

By the end of this section I can calculate the perimeter of a rectangle and solve practical fencing problems — so I can order the right amount of fencing for each dinosaur enclosure.

Success criteria 0 / 4 ticked

Tick each one when you can do it without help.

1A What is perimeter?

The perimeter is the total distance around the outside of a shape. For a dinosaur enclosure, that is exactly how much fencing you need to build the boundary.

The perimeter formula for a rectangle

perimeter rectangle metres (m)

A rectangle has two pairs of equal sides. Add the length and the width, then double the total — because there are two lengths and two widths:

P = 2 × (length + width)

If the length is L and the width is W, the perimeter is 2 × (L + W). The unit is metres (m) because we are measuring length.

Stegosaurus enclosure

Length = 6 m, Width = 4 m given dimensions
P = 2 × (6 + 4) apply the formula
P = 2 × 10 = 20 m so 20 metres of fencing are needed

Check yourself

A Brachiosaurus enclosure is 9 m long and 5 m wide. How many metres of fencing are needed to go all the way around?

m
Add the length and width together first, then double the result.
P = 2 × (length + width) = 2 × (9 + 5) = 2 × 14 = 28 m

The park has 36 m of fencing for a rectangular Ankylosaurus enclosure. If the length is 10 m, what is the width in metres?

m
Halve the perimeter to get length + width, then subtract the known length.
Perimeter = 36, so length + width = 36 ÷ 2 = 18. Width = 18 − 10 = 8 m

1B Building enclosures on the grid

Use the grid below to build a rectangular enclosure. Each grid square represents 1 metre. Watch how the perimeter updates as you change the length and width.

Interactive · build a rectangle and read the perimeter

5
3

Check yourself

An Iguanodon enclosure has a perimeter of 30 m. If the length is 11 m, what is its width?

m
Divide the perimeter by 2 to find the sum of length and width.
30 ÷ 2 = 15, so length + width = 15. Width = 15 − 11 = 4 m

A square Velociraptor enclosure has sides of 8 m each. How much fencing is needed to surround it?

m
A square has four equal sides, so multiply one side by 4.
P = 4 × 8 = 32 m

Section 2 · Area

Room for the Dinosaurs

By the end of this section I can calculate the area of a rectangle and solve practical space problems — so I can check each dinosaur has enough ground space in its enclosure.

Success criteria 0 / 4 ticked

Tick each one when you can do it without help.

2A What is area?

The area is the amount of flat surface inside a shape — the ground space a dinosaur can actually roam on. For a rectangle, you can find it by counting 1-metre squares or by multiplying.

The area formula for a rectangle

area rectangle square metres (m²)

Multiply the length by the width. Each row has length squares, and there are width rows — so the total number of squares is:

A = length × width

Area is measured in square metres (m²) because we are counting squares that are 1 metre on each side.

Triceratops enclosure

Length = 8 m, Width = 5 m given dimensions
A = 8 × 5 apply the formula
A = 40 m² so the Triceratops has 40 square metres of space

Check yourself

A Parasaurolophus enclosure is 8 m long and 6 m wide. What area of ground space does it provide?

Multiply the length by the width to count the square metres inside.
A = length × width = 8 × 6 = 48 m²

A Pachycephalosaurus needs 72 m² of space. If the enclosure is 9 m wide, what length must it be?

m
Divide the area by the known side to find the other dimension.
Length = area ÷ width = 72 ÷ 9 = 8 m

2B Same fencing, different space

Two enclosures can have the same perimeter but different areas. The shape matters! Use the grid to see how the area changes as you adjust the dimensions — each filled square is 1 m² of dinosaur space.

Interactive · fill the enclosure and count the square metres

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4

Check yourself

Two enclosures each have 24 m of fencing. One is 8 m × 4 m and the other is 6 m × 6 m. What is the larger area, in square metres?

Calculate each area separately, then state the larger of the two.
First: 8 × 4 = 32 m². Second: 6 × 6 = 36 m². The larger area is 36 m² — the square enclosure wins.

A Carnotaurus enclosure is 12 m long and 7 m wide. What is its area in square metres?

Multiply the two dimensions to count the square metres inside.
A = length × width = 12 × 7 = 84 m²

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